Question

Calculati procentul de oxigen continut intr-un amestec de oxid cupros si cupric daca se gasesc in raport molar de 1/2 si raport masic = 1/2..

Answer 1

MCu2O=144g/mol
MCuO=80g/mol
raportul molar este 1/2
consideram un mol Cu2O (144g) in care exista 16g O
consideram 2moli CuO (2*80g) in care exista 32g O
masa amestec oxizi=144+160=304g
in 304 g amestec...........(16+32)g O
     100g amestec................x=100*48/304=15,78% O