Question

Calculati:
rad 625/81 ÷rad 25/9 +3intregi 1/3 :rad 1,(7) -are 36÷rad 6⁴​

Answer 1

$\sqrt{ \frac{625}{81} } \div \sqrt{ \frac{25}{9} } + 3\frac{1}{3} \div \sqrt{1.(7)} - \sqrt{36 } \div \sqrt{ {6}^{4} } = \\ = \frac{ \sqrt{625} }{ \sqrt{81} } \div { \frac{ \sqrt{25} }{ \sqrt{9} } } + \frac{3 \times 3 + 1}{3} \div \sqrt{1 \frac{7}{9} } - 6 \div {6}^{2} = \\ = \frac{25}{9} \div \frac{5}{3} + \frac{10}{3} \div \sqrt{ \frac{16}{9} } - \frac{6}{36} = \\ = \frac{25}{9} \times \frac{3}{5} + \frac{10}{3} \div \frac{ \sqrt{16} }{ \sqrt{9} } - \frac{1}{6} = \\ = \frac{5}{3} + \frac{10}{3} \div \frac{4}{3} - \frac{1}{6} = \\ = \frac{5}{3} + \frac{10}{3} \times \frac{3}{4} - \frac{1}{6} = \\ = \frac{5}{3} + \frac{5}{2} - \frac{1}{6} = | \times 6 \\ = \frac{5 \times 2 + 5 \times 3 - 1}{6} = \\ = \frac{10 + 15 - 1}{6} = \\ = \frac{24}{6} = \\ = 4$