Question

Calculati: (radical din 27 minus 4 )(3radical din 3 plus 4) ,a rog ajutati-ma

Answer 1

(√27 - 4)(3√3 + 4) = √27 * 3√3 + 4√27 - 12√3 - 16 = 3√81 + 4√27 - 12√3 - 16 = 3 * 9 + 4√27 - 12√3 - 16 = 27 + 4√24 - 12√3 - 16 = 11 + 4√24 - 12√3.

Answer 2

($\sqrt{27} -4)$($3\sqrt{3} + 4)$=
[tex]=( 3\sqrt{3}-4 )(3 \sqrt{3}+4 ) [/tex]
=$( 3\sqrt{3} ) ^{2} - 4^{2}$
=$27-16$
=$11$