Question

calculati? (radical din 5 + 1)la a 2a + (radical din 5 -1) la a 2a=12

Answer 1

$( \sqrt{5} +1)^2+( \sqrt{5} -1)^2= \sqrt{5} ^2+2* \sqrt{5} *1+1^2+ \sqrt{5} ^2-2* \sqrt{5} *1+1^2 \\ =5+2 \sqrt{5} +1+5-2 \sqrt{5} +1=5+1+5+1=6+6=12$