Question

calculati radical din 6 ( 4 radical din 2 + 5x ) = 13 radical din 3

Answer 1

$\sqrt{6} (4 \sqrt{2} + 5x) = 13 \sqrt{3} = > 4 \sqrt{12} + 5 \sqrt{6} x = 13 \sqrt{3} = > 8 \sqrt{3} + 5 \sqrt{6} = 13 \sqrt{3} = > 5 \sqrt{6} x = 13 \sqrt{3} - 8 \sqrt{3} = > 5 \sqrt{6} x = 5 \sqrt{3} = > x = \frac{1}{ \sqrt{2} } = > x = \frac{ \sqrt{2} }{2}$