Question

calculati raport-ul de masa si compozitia procentuala pt sulfat de calciu dau coroana.

Answer 1

Sulfatul de calciu: CaSO4
masa sulfatului = 40 + 32 + 4*16 = 136 g
%Ca = m calciu/m sulfat * 100 = 40/136 * 100 = 29.411%
%S= m sulf/m sulfat * 100 = 32/136 * 100 = 23,529%
%O = m oxigen/m sulfat * 100 = 4*16/136 * 100 = 47,158%
Raportul de masa:
m Ca: m S: m O = 40:32:4*16 = 5:4:8

Answer 2

CaSO₄ ⇒ sulfat de calciu

MCaSO₄ = ACa+AS+4AO = 40+32+4*16=136g/mol

mCa = 40g         mS=32g          mO=4*16=64g

raport de masa ⇒ mCa:mS:mO=40:32:64 = 5:4:8

%Ca=mCa/MCaSO4*100 = 40/136*100 = 29,411%

%S=mS/MCaSO4*100=32/136*100 = 23,5294%

%O=mO/MCaSO4*100=64/136*100 = 47,0588%