Question

Calculati raportul atomic ,raportul de masa ,compozitia procentuala.pentu
V₂O₅.
AgNo₃.
CrCl₃.
H₃po₃
dau coroaa
va rog e urgent

Answer 1

V₂O₅
raportul atomic = 2:5
raportul de masa = 51*2:16*5 = 102:80 = 51:40
compozitia procentuala
51*2+16*5=182
ω(V)=102*100%/182=56,04%
ω(O)=80*100%/182=43,96%

AgNO₃
raportul atomic=1:1:3
raportul de masa=108:14:16*3=108:14:48=54:7:24
compozitia procentuala
108+14+16*3=170
ω(Ag)=108*100%/170=63,52%
ω(N)=14*100%/170=8,24%
ω(O)=48*100%/170=28,24%

CrCl₃
raportul atomic=1:3
raportul de masa=52:3*35=52:105
compozitia procentuala
52+105=157
ω(Cr)=52*100%/157=33,12%
ω(Cl)=105*100%/157=66,88%

H₃PO₃
raportul atomic=1:1:3
raportul de masa=1*3:1*31:3*16=3:31:48
compozitia procentuala
3+31+48=82
ω(H)=3*100%/82=3,66%
ω(P)=31*100%/82=37,80%
ω(O)=48*100%/82=58,54%