Question

Calculati raportul atomic si raportul de masa si comozitia procentuala pentru carbonatul de calciu.Urgent !Dau coroana

Answer 1

CaCO3

r.a.=1Ca :1Ca :3O=1:1:3

r.m.=ACa :AC :3AO=40:12:3.16=40:12:48=10:3:12

Compozitie procentuala prin masa moleculara

M=40+12+48=100------>1mol=100g

1oog CaCO3--------40 g Ca--------12 g C---------48 g O

100g ---------------------x------------------y-----------------z

x=100.40:100=40 la suta Ca

y=100.12:100=12 la suta

z 100.48:100=48 la suta O