Question

Calculati raza cercului circumscris triunghiului ABC , cu AB=16 cosC=3/5

Answer 1

[tex]\sin C=\sqrt{1-\cos^2C}=\sqrt{1-(\frac{3}{5})^2}=\frac{4}{5}\\ \frac{AB}{\sin C}=2R \Rightarrow R=\frac{AB}{2\sin C}=\\ =\frac{16}{2\frac{4}{5}}=10[/tex]