Question

Calculați respectând ordinea efectuări operațiilor : a) [(2·3·5)^2-2^8:2^6]:4-2^3:5^2
b)2^77:(2^5·2^10)^5+5·(352-350:2)
c)3^100[3^40·3^58-(3^10·3^15)^5:3^27+(4^57:4^56-1^2014)^97]·7
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Answer 1

a)
[(2·3·5)^2-2^8:2^6]:4-2^3:5^2 =
= (30^2 - 2^2) : 4 - 8 : 25 =
= (600 - 4):4 - 8:25 =
= 896 : 4 - 8:25 =
= 224 - 0,32 =
= 223,68

b)
2^77:(2^5·2^10)^5+5·(352-350:2) =
= 2^77 : (2^15)^5 + 5×(352 - 175) =
= 2^77 : 2^75 + 5 × 177 =
= 2^2 + 885 =
= 4 + 885 =
= 889

c)
3^100[3^40·3^58-(3^10·3^15)^5:3^27+(4^57:4^56-1^2014)^97]·7 =

=3^100[3^98-(3^25)^5:3^27+(4 - 1)^97]×7=

= 3^100(3^98-3^125:3^27+3^97) × 7 =

= 3^100(3^98-3^98 + 3^97) × 7 =

= 3^100 × 3^97 × 7 =

= 3^3 × 7 =

= 27 × 7 =

= 189