Calculati, respectand ordinea efectuarii operatiilor:
a)93:3+41x5-45:9+28:7+81:3-2x6
b){7+7x[7+3x(5+225:15-15)]}-161
c)10x{2+10x[126+10x(24+24:2-6)]}-42.600
Va rog sa scrieti pas cu pas nu direct
Răspunsuri la întrebare
Răspuns:
a) 93:3+41×5-45:9+28:7+81:3-2×6=250
31+205-5+4+27-12=
236-5+4+27-12=
231+4+27-12=
235+27-12=
262-12=250
b) {7+7×[7+3×(5+225:15-15)]}-161=0
{7+7×[7+3×(5+15-15)]}-161=
{7+7×[7+3×(20-15)]}-161=
[7+7×(7+3×5)]-161=
[7+7×(7+15)]-161=
(7+7×22)-161=
(7+154)-161=
161-161=0
a) 93:3+41x5-45:9+28:7+81:3-2x6=
=31+205-5+4+27-12
=236-5+4+27-12
=231+4+27-12
=235+27-12
=262-12
=250
b){7+7x[7+3x(5+225:15-15)]}-161
={7+7x[7+3x(5+15-15)]}-161
={7+7x[7+3x(20-15)]}-161
=[7+7x(7+3x5)]-161
=[7+7x(7+15)]-161
=(7+7x22)-161
=(7+154)-161
=161-161
=0
c)10x{2+10x[126+10x(24+24:2-6)]}-42.600 (am luat punctul ca si ori)
=10x{2+10x[126+10x(24+12-6)]}-42x600
=10x{2+10x[126+10x(36-6)]}-42x600
=10x[2+10x(126+10x30)]-42x600
=10x[2+10x(126+300)]-42x600
=10x(2+10x426)-42x600
=10x(2+4260)-42x600
=10x4262-42x600
=42620-25200
=17420
Sper ca te-am ajutat