Question

Calculati,respectand reguliile de invatat:∑→ aceasta este paranteza dreapta.
- 225-2x∑(107+13)-(104+8)=?
-106+12x∑1000-75:5x(96:3:2:8)∑=?
- ∑(75+5)x9-20∑:100=?
-∑150:10+25)+85∑=?
- 2x∑(0:90+90:5)+123:3-10)∑+999:9x3=?
-600+480:4-∑68:2+4x(20+12-18)∑=?
- 6+10∑362-10x(42+42:6)∑x0=?
Cine ma ajuta primul promit ca dau coroana pentru cel mai bun raspuns. :-)

Answer 1

225-2x[(107+13)-(104+8)]=223-2x(117-112)=223-2x5=223-10=213
-106+12x[1000-75:5x(96:3:2:8)]=106+12x(1000-15x2)=106+12x960=106+11520=11626
- [(75+5)x9-20]:100=(80x9-20):100=(720-20):100=700:100=7
-[(150:10+25)+85]=(15+25)+85=35+85=120
- 2x[(0:90+90:5)+(123:3-10)]+999:9x3=2x(0+58)+(41-10)+111x3=116+31+333=480
-600+480:4-[68:2+4x(20+12-18)]=600+120-(34+4x14)=720-90=630
- 6+10 aici e x[362-10x(42+42:6)]x0=