Question

calculati,respectand regulile invatate:
[593+126x8-(368:4+707)]x100=?
[(480:2+50:2)x3-65x4]x3+4x0=?
225-2x`(107+13)(104+8)]=?
106+12x[1.000-75:5x(96:3:2:8)]=?
[(75+5(x9-20]:100=?
[(150:10+25)+85]:5=?
2x[(0:90+90)+123:3-10)]+999:9x3=?
600+480:4-[68:2+4 x(20+12-18)]=?
6+10x[362-10x(42+42:6)]x0=?

Answer 1

[593+126x8-(368:4+707)]x100=
=[593+1008-(92+707)]x100=
=(593+1008-799)x100=
=(593+1008-799)x100=
=802x100=80200

[(480:2+50:2)x3-65x4]x3+4x0=
=[(240+25)x3-260]x3=
=(265x3-260)x3=
=535x3=
=1605

225-2x(107+13)(104+8)]=
=225-2x120x112=
=225-26880=
=-26655

106+12x[1.000-75:5x(96:3:2:8)]=
=106+12x(1.000-15x2)=
=106+12x(1.000-30)=
=106+12x970=
=106+11640=
=11746

[(75+5)x9-20]:100=
=(80x9-20):100=
=(720-20):100=
=700:100=
=7

[(150:10+25)+85]:5=
=[(15+25)+85]:5=
=(40+85):5=
=125:5=25

2x[(0:90+90)+123:3-10)]+999:9x3=
=2x[(0+90)+41-10)]+111x3=
=2x(90+41-10)+333=
=2x121+333=242+333=575

600+480:4-[68:2+4 x(20+12-18)]=.
=600+120-(34+4 x14)=.
=720-(34+56)=
=720-90=
=630

6+10x[362-10x(42+42:6)]x0=
=6+10x[362-10x(42+42:6)]x0=
=6