Question

Calculati, respectand regulile invatate. a)[267+117×9-(832÷2-531÷9)]×10 = c)[2100÷(225-500÷4)+(84÷2×0)]×100÷10÷10= c) 3+6×[30+6×(3+5×6)-28]-3=

Answer 1

ca sa stii eu nu mai scriu exercițiul scriu direc rezolvarea
a) [267+1053-(416-59)]×10=
=(1320-357)×10=
=963×10=
=9630
b) [2100÷(225-125)+0]×100÷10÷10=
=(2100÷100+0)×100÷10÷10=
=21×100÷10÷10=
=2100÷10÷10=
=210÷10=
=21
c) 3+6×[30+6×(3+30)-28]-3=
=3+6×(30+6×33-28)-3=
=3+6×(30+198-28)-3=
=3+6×(228-28)-3=
=3+6×200-3=
=3+1200-3=
=1200