Question

Calculati, respectând regulile învățate. a) [267+117×9-(832:2-531:9)]×10=??? b) 30+4×[36:9+3×(20+8+42:2)]=??? c) [2100:(225-500:4)+(84:2×0)]×100:10:10=??? d) 9×(101×1+111:1)-[85-7×(36:9+63:9)]=??? e) 3+6×[30+6×(3+5×6)-28]-3=??? f) 2+2×[2+3×(2+202:2-306:3)]=??? Va rog din sufletul ajutati-ma va rogggg

Answer 1

a) [267+117*9-(832:2-531:9)]*10=
=[267+1053-(416-59)]*10=
=(267+1053-357)*10=
=(1320-357)*10=
=963*10=
=9630

b) 30+4*[36:9+3*(20+8+42:2)]=
=30+4*[4+3*(28+21)]=
=30+4*(4+3*49)=
=30+4*(4+147)=
=30+4*151=
=30+604=
=634

c)[2100:(225-500:4)+(84:2*0)]*
*100:10:10=
=[2100:(255-125)+(42*0)]*10:10=
=(2100:100+0)*1=
=(21+0)*1=
=21*1=
=21

d) 9*(101*1+111:1)-[85-7*(36:9+63:
:9)]=
=9*(101+111)-[85-7*(4+7)]=
=9*212-(85-7*11)=
=1908-(85-77)=
=1908-8=
=1900

e) 3+6*[30+6*(3+5*6)-28]-3=
=3+6*[30+6*(3+30)-28]-3=
=3+6*(30+6*33-28]-3=
=3+6*(30+198-28)-3=
=3+6*(228-28)-3=
=3+6*200-3=
=3+1200-3=
=1203-3=
=1200

f) 2+2*[2+3*(2+202:2-306:3)]=
=2+2*[2+3*(2+101-102)]=
=2+2*[2+3*(103-102)]=
=2+2*(2+3*1)=
=2+2*(2+3)=
=2+2*5=
=2+10=
=12

Sper că te-am ajutat!
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