Question

Calculati, respectând regulile învățate. a) [267+117×9-(832:2-531:9)]×10=??? b) 30+4×[36:9+3×(20+8+42:2)]=??? c) [2100:(225-500:4)+(84:2×0)]×100:10:10=??? d) 9×(101×1+111:1)-[85-7×(36:9+63:9)]=??? e) 3+6×[30+6×(3+5×6)-28]-3=??? f) 2+2×[2+3×(2+202:2-306:3)]=??? Va rog din sufletul ajutati-ma va rogggg

Answer 1

[267+117x 9-(416-59)]x10=(267+117X9-357)X10=(267+1053-357)X10=(1320-357)X10=963X10=9630
B.30+4X[36:9+3X(20+8+21)]=30+4X(36:9+3X49)=30+4X(4+147)=30+4X151=30+604=634
C.[2100:(225-125)+(42X0)]X100:10:10=(2100:100+0)X100;10:10=(21+0)X100:10:10=21X100:10:10=2100:10:10=210:10=21
D.
9X(101+111)-[85-7X(4+7)]=9X212-(85-7X11)=9X212-(85-77)=9X212-8=1908-8=1900
E.3+6X[30+6X(3+30)-28]-3=3+6X(30+6X33-28)-3=3+6X(30+198-28)-3=3+6X(228-28)-3=3+6X200-3=3+1200-3=1203-3=1200
F.2+2X[2+3X(2+101-102)]=2+2X[2+3X(103-102)]=2+2X(2+3X1)=2+2X(2+3)=2+2X5=2+10=12