Question

Calculati respectand regulile invatate e 3+6×[30+6×(3+5×6)-28]-3 f 2+2×[2+3×(2+202:2-306:3)]

Answer 1

2 + 2 x [ 2 + 3 x ( 2 + 202 : 2 - 306 : 3 )]=
2 + 2 x [ 2 + 3 x ( 2 + 101 - 102 )]=
2 + 2 x [ 2 + 3 x 1 ] = 
2 + 2 x [ 2 + 3 ] =
2 + 2 x 5 =
2 + 10 = 12

3 + 6 x [ 30 + 6 x ( 3 + 5x 6 ) - 28 ] - 3 =
3 + 6 x [ 30 + 6 x ( 3 + 30 ) - 28 ] - 3 =
3 + 6 x [ 30 + 6 x 33 - 28 ] - 3 =
3 + 6 x [ 30 + 198 - 28 ] - 3 =
3 + 6 x 200 - 3 =
3 + 1200 - 3 =
1203 - 3 = 1200