Question

Calculati scotand factorul comun a) 2/5*7+3*7-7*12/5 b)3/19*3/7+3/19*4/7 c)2/23*3/5-2/5*3/46 d)5*7/11+5*3/22-5*1/2 Dau coronita va rog rezolvati rapid!!!

Answer 1

a) 2/5*7+3*7-7*12/5=
=7×(2/5+3-12/5 )=
=7×(2/5+3/1 -12/5)=
=7× 2+5×3-12tot ăsta supra/5=
=7× 17-12totulsupra/5=
=7 × 5/5=
=7× 1=
=7

b)3/19*3/7+3/19*4/7=
=3/19×(3/7+4/7)=
=3/19× 7/7=
=3/19 ×1=
=3/19

c)2/23*3/5-2/5*3/46=
=
aici nu stiu daca e cu minus 2/5 , dar daca ai notat gresit una dintre ele ori ambele se înmulțesc cu 3/5 ori cu 2/5

daca e cu 3/5 =>
c)2/23*3/5-3/5*3/46=
=3/5×(2/23 -3/46)=
=3/5× 2×2-3tot asta/46=
=3/5×1/46=
=3×1 totul/5×46=
=3/230

mai degrabă cred ca este cu 2/5 =>
c)2/23*2/5-2/5*3/46=
=2/5×(2/23-3/46)=
=2/5× 2×2-3tot asta/46=
=2/5 × 1/46=
=1×1 totul supra/5×23=
=1/115




d)5*7/11+5*3/22-5*1/2=
=5×(7/11+3/22-1/2)=
=5× 2×7+3-11×1tot asta supra/22=
=5× 14-11totul supra/22=
=5× 3/22=
=5/1×3/22=
=5×3 totul supra/1×22=
=15/22