Question

Calculati si gasiti numarul divizorilor sumelor:
a)S=2¹⁴+2¹⁶+2¹⁸
b)S=3¹⁵+3¹⁶+ 3 la 17

Answer 1

a) S= $2^{14} (1+ 2^{2} + 2^{4} )$
S=$2^{14} *3*7$  => nr. div= (14+1)(1+1)(1+1)=60
b) S=$3^{15} (1+3+ 3^{2} )$
S=$3^{15} *13$ => nr. div=(15+1)(1+1)=32