calculati suma numerelor naturaale care impartite la 8 dau catul 13
Răspunsuri la întrebare
a:8=13 rest 0
a=13x8
a=104
a:8=13 rest 1
a=13x8+1
a=105
Si tot asa pana la restul 7.
a=104, 105, 106, ..., 111
Si suma lor este:
104+105+106+...+111=
104+111+105+110+106+109+107+108=
215+215+215+215=
4x215=
=860
Succes!
a : 8 = 13 rest 0
a = 13 × 8 + 0
a = 104 + 0
a = 104
b : 8 = 13 rest 1
b = 13 × 8 + 1
b = 104 + 1
b = 105
c : 8 = 13 rest 2
c = 13 × 8 + 2
c = 104 + 2
c = 106
d : 8 = 13 rest 3
d = 13 × 8 + 3
d = 104 + 3
d = 107
e : 8 = 13 rest 4
e = 13 × 8 + 4
e = 104 + 4
e = 108
f : 8 = 13 rest 5
f = 13 × 8 + 5
f = 104 + 5
f = 108
g : 8 = 13 rest 6
g = 13 × 8 + 6
g = 104 + 6
g = 110
h : 8 = 13 rest 7
h = 13 × 8 + 7
h = 104 + 7
h = 111
104 + 105 + 106 + 107 + 108 + 109 + 110 + 111 = 209 + 106 + 107 + 108 + 109 + 110 + 111 = 315 + 107 + 108 + 109 + 110 + 111 = 422 + 108 + 109 + 110 + 111 = 530 + 109 + 110 + 111 = 639 + 110 + 111 = 749 + 111 = 860 => suma numerelor