Question

calculati suma numerelor naturale care impartite la 8 dau 5

Answer 1

n:8=5 si rest mai mic ca 8

n=8x5+0=40

n=8x5+1=41

n=8x5+2=42

n=8x5+3=43

n=8x5+4=44

n=8x5+5=45

n=8x5+6=46

n=8x5+7=47

s=40+41+42+43+44+45+46+47=348

Answer 2

A:8=5si r<8

A=8×5+0=40

A=8×5+1=41

A=8×5+2=42

A=8×5+3=43

A=8×5+4=44

A=8×5+5=45

A=8×5+6=46

A=8×5+7=47

40+41+42+43+44+45+46+47=348