Question

calculati suma numerelor naturale care impartite la 8 dau catul 5​

Answer 1

Răspuns:

a:8=5

R <I=>R=0,1,2,3,4,5,6,7

a:8=5 rest 0=>a=8·5+0=>a=40

a:8=5 rest 1=>a=8·5+1=>a=41

.

a:8=5 rest 7=>a=8·5+7=>a=47

40+41+42+43+44+45+46+47=348

Answer 2

a : 8 = 5 rest 0

a = 5 × 8 + 0

a = 40 + 0

a = 40

b : 8 = 5 rest 1

b = 5 × 8 + 1

b = 40 + 1

b = 41

c : 8 = 5 rest 2

c = 5 × 8 + 2

c = 40 + 2

c = 42

d : 8 = 5 rest 3

d = 5 × 8 + 3

d = 40 + 3

d = 43

e : 8 = 5 rest 4

e = 5 × 8 + 4

e = 40 + 4

e = 44

f : 8 = 5 rest 5

f = 5 × 8 + 5

f = 40 + 5

f = 45

g : 8 = 5 rest 6

g = 5 × 8 + 6

g = 40 + 6

g = 46

h : 8 = 5 rest 7

h = 5 × 8 + 7

h = 40 + 7

h = 47

40 + 41 + 42 + 43 + 44 + 45 + 46 + 47 =

81 + 42 + 43 + 44 + 45 + 46 + 47 =

123 + 43 + 44 + 45 + 46 + 47 =

166 + 44 + 45 + 46 + 47 =

210 + 45 + 46 + 47 =

255 + 46 + 47 =

301 + 47 = 348 => suma numerelor