Question

calculați suma numerelor naturale care impartite la 9 dau dau catul 4​

Answer 1

a : 9 = 4 rest 0

a = 4 × 9 + 0

a = 36 + 0

a = 36

b : 9 = 4 rest 1

b = 4 × 9 + 1

b = 36 + 1

b = 37

c : 9 = 4 rest 2

c = 4 × 9 + 2

c = 36 + 2

c = 38

d : 9 = 4 rest 3

d = 4 × 9 + 3

d = 36 + 3

d = 39

e : 9 = 4 rest 4

e = 4 × 9 + 4

e = 36 + 4

e = 40

f : 9 = 4 rest 5

f = 4 × 9 + 5

f = 36 + 5

f = 41

g : 9 = 4 rest 6

g = 4 × 9 + 6

g = 36 + 6

g = 42

h : 9 = 4 rest 7

h = 4 × 9 + 7

h = 36 + 7

h = 43

i : 9 = 4 rest 8

i = 4 × 9 + 8

i = 36 + 8

i = 44

36 + 37 + 38 + 39 + 40 + 41 + 42 + 43 + 44 =

73 + 38 + 39 + 40 + 41 + 42 + 43 + 44 =

111 + 39 + 40 + 41 + 42 + 43 + 44 =

150 + 40 + 41 + 42 + 43 + 44 =

190 + 41 + 42 + 43 + 44 =

231 + 42 + 43 + 44 =

273 + 43 + 44 =

316 + 44 = 360 => suma numerelor