Question

Calculati
[tex]2(3x+1)+(1-2x)=
[/tex]
$x*x+x+x:x=$
$x^{8} : x^{7} + x^{6} : x^{5} - x^{4} : x^{3} + x^{2} :x =$
$(x-2)(x+2)+4=$
$(x+4)(x-3)-x+12=$

Answer 1

$2(3x+1)+(1-2x)=6x+2+1-2x=4x+3$
$x*x+x+x:x= x^{2} +x+1$
$x^{8} : x^{7} + x^{6} : x^{5}-x ^{4} : x^{3} + x^{2} :x=x^{8-7} +x^{6-5}-x^{4-3}+x^{2-1}=$$x+x-x+x=2x$
$(x-2)(x+2)= x^{2} +2x-2x-4= x^{2} -4$
$(x+4)(x-3)-x+12= x^{2} -3x+4x-12-x+12= x^{2}$