Question

Calculati:$(2^8)^2 : 2^2^4 x (3^2-1)-3^0 x 2^2$

Answer 1

[tex] (2^8)^2 : (2^2)^4 * (3^2-1)-3^0 * 2^2\\ =2^{16}:2^{8}*8-1*4\\ =2^{16-8}*8-1*4\\ =2^8*8-4\\ =256*8\\ =2048-4\\ =2044[/tex]