Question

Calculati: $(3\sqrt{2}-2 \sqrt{3}) ( \sqrt{18}+ \sqrt{12}):( \sqrt{75}- \sqrt{27})=$

Answer 1

√18=3√2
√12=2√3
√75=5√3
√27=3√3
⇒(3√2-2√3)(3√2+2√3):(5√3-3√3)=
=(18+6√6-6√6-12):2√3=6/2√3=rationalizam=6√3/6=√3

Answer 2

[tex]=(3 \sqrt{2} -2 \sqrt{3})( \sqrt{9*2} + \sqrt{4*3} ):( \sqrt{25*5} - \sqrt{9*3} )\\ =(3 \sqrt{2}-2 \sqrt{3})*( 3\sqrt{2} +2 \sqrt{3} ):(5 \sqrt{5} -3 \sqrt{3)} \\ =(18+ 6\sqrt{6}-6 \sqrt{6} -12 ):2 \sqrt{3} \\ = \frac{6}{ 2\sqrt{3} }(rationalizam)\\ = \frac{6 \sqrt{3} }{6} (simplificam~6~cu~6)\\ \boxed{= \sqrt{3} } [/tex]