Question

Calculati:
$5 \sqrt{12 {y}^{3} } - 4 \sqrt{27 {y}^{3} } - \sqrt{108 {y}^{3} } + \sqrt{48 {y}^{3} } =$
Dau coroana!

Answer 1

5·2y√3y-4·3y√3y-6y√3y+4y√3y=
√3y·( 10y-12y-6y+4y)=
-4y√3y