Question

Calculati:
$a)( 2\frac{3}{8}+3 \frac{7}{24}):(4 \frac{2}{3}-1 \frac{1}{8}) b) (5 \frac{3}{5}-1\frac{1}{3}):(7\frac{7}{12}-2\frac{1}{4})$
Va rog :3

Answer 1

$a) ( \frac{2x8+3}{8} + \frac{3x24+7}{24}$$:( \frac{4x3+2}{3} - \frac{1x8+1}{8}$$= (\frac{19}{8} + \frac{79}{24} ):( \frac{15}{3} - \frac{9}{8} )= \frac{19x3+79}{24}: \frac{15x8-9x3}{24}= \frac{57+79}{24}: \frac{120-27}{24}= [tex] \frac{136}{24} : \frac{93}{24} =[tex] \frac{136}{24} x \frac{24}{93}$=$\frac{136}{93}$