Question

calculati:

$C^{2}_ 3 + P_4 - A_4 ^1$

Answer 1

1. la combinari e formula= n!/k!*(n-k)!
2. combinari de 3 luate cate 2=3
3. permutari de 4 inseamna 4! deci 1*2*3*4=24
4. la aranjamente formula e n!/(n-k)! deci aranjamente de 4 luate cate 1 este 4
5. revenim la calcul
6. 3+24-4=27-4=23