Question

Calculați : 
$\frac{1}{2}$ + 1,1(6) + 1,(3) : [ 0,(6)] la puterea a 2-a

Answer 1

$\dfrac12+\dfrac{116-11}{90}+\dfrac{13-1}{9}:\left(\dfrac69\right)^2=\dfrac12+\dfrac76+\dfrac43\cdot\dfrac94=\dfrac12+\dfrac76+3=$

$=\dfrac{3+7+18}{6}=\dfrac{28}{6}=\dfrac{14}{3}=4\dfrac23=4,(6)$