Question

calculati

$( \frac{2}{ \sqrt{3} } + \frac{3}{ \sqrt{2} } )* \sqrt{6} - ( \frac{1}{2 \sqrt{3} } + \frac{2}{ \sqrt{8} } )* \sqrt{24}$

Answer 1

$\frac{2 \sqrt{3} }{3} + \frac{3 \sqrt{2} }{2} * \sqrt{6} -( \frac{ \sqrt{3} }{6}+ \frac{ \sqrt{2} }{2})*2 \sqrt{6}$
Se,aduc,la,numitor,comun,parantezele
$( \frac{4 \sqrt{3}+9 \sqrt{2} }{6})* \sqrt{6}-( \frac{ \sqrt{3}+3 \sqrt{2} }{6} )*2 \sqrt{6} =$
$\frac{4 \sqrt{18}+9 \sqrt{12} -2 \sqrt{18}-6 \sqrt{12} }{6} =$
·$\frac{2 \sqrt{18} +3 \sqrt{12} }{6} = \frac{6( \sqrt{2}+ \sqrt{3}) }{6} = \sqrt{2} + \sqrt{3}$