Question

Calculati :

($\sqrt{3}$ - 2 ) + ( $\sqrt{3}$ - 2 ) supra $\sqrt{2}$ - $\sqrt{3}$

[ 2x + 1 ] supra 3 = 3x-2

Cine ma poate ajuta urgent ? 

Answer 1

2(√3-2)/(√2-√3)=2(√3-2)(√2+√3)/(2-3)=
2(√6-2√2+3-2√3)/(-1)=-2(√6-2√2+3-2√3)

(2x+1)/3=3x-2
2x+1=9x-6
7x=7
x=1