Question

Calculati$( \sqrt{8} - 3 \sqrt{2} + \sqrt{10})*( \sqrt{2}+ \sqrt{1,6}+3 \sqrt{0,4})$

Answer 1

(√8 - 3√2+√10)*(√2+√1,6+3√0.4)=
(2√2 - 3√2 +√10)*(√2+√1,6+3√0,4)=
(-√2+√10)*(√2+√1,6+3√0,4)=
-√2*√2-√2*√1,6-√2* 3√0.4+√10*√2+√10*√1,6+√10* 3√0,4=
-2-√2*16/10 - √2*4/10 * 3 +√20 + √16 + 3√4=
-2- √16/5 - √4/5*3 + 2√5 + 4 +3*2= (adunam 2 cu -4 si cu 3*2 adica 6)
8- 4/√5 - 2*3/√5 + 2√5=
8+ (-4-6)/√5 + 2√5=
8 - 10/√5 + 2√5= (rationalizam numitorul √5)
8- (10√5)/5 + 2√5=
8- 2√5 + 2√5=
8-0=
8

Sper sa intelegi si sa te ajute raspunsul meu !! :)