Question

Calculati tinand cont de ordinea efectuarii operatiilor:
a) 3/2 + 5 :(12/5 + 0,(3) )=
b) 1/2 + 2 x(0,25+3)
c) -3,25 + 3 x(1,7 - 3/2)
d) [1/3 + 1/3 : (1 - 1/3)] : 3/2
e) 10,1 : [(6/5 + 13/6) x ( 21/10 + 6/13)] :1,(4)

Answer 1

Răspuns:

3/2+5:[12/5+0,(3)]=

3/2+5:(12/5+3/9)=

3/2+5:(³⁾12/5+⁵⁾1/3)

3/2+5:41/15=

3/2+5·15/41=

⁴¹⁾3/2+²⁾75/41=

123/82+150/82=273/82

______________

1/2 + 2 x(0,25+3)=

1/2+2·3,25=

0,5+6,5=7

__________________

-3,25 + 3 x(1,7 - 3/2)=

-3,25+3·(1,7-1,5)=

-3,25+3·0,2=

-3,25+0,6= -2,65

_______________

[1/3+1/3:(1-1/3)]÷3/2=

(1/3+1/3:2/3):3/2=

(1/3+1/3·3/2):3/2=

(1/3+1/2):3/2=

5/6:3/2=

5/6·2/3=5/9

_____________________

10,1:[(⁶⁾6/5 +⁵⁾13/6 )x (¹³⁾21/10 +¹⁰⁾6/13 ]:1,(4) =

101/10 :[(36/30+65/30)·(273/130+60/130) ] :13/90 =

101/10 :(101/30·333/130 ) :13/90 =

=90/111=0,(810)

1,(4)=(14-1)/90=13/90