Question

Calculați ultima cifră a nr: 22^2020+176^2019+2018^0



Repede vă rog frumos


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Answer 1

Explicație pas cu pas:

u(2^1)= 2

u(2^2)= 4

u(2^3)=8

u(2^4)= 6

u(2^5)= 2

2020:4=505, rest 0

deci, u(2^2020)= 6

u(6^1)=6

u(6^2)=6

u(6^2019)= 6

2018^0= 1

u(22^2020+176^2019+2018^0) = u(6+6+1)= 3