Question

Calculati urmatoarele exercitii:
a) (2√32-10√14) : (2√2) -(3√90-√3240):(3√5) =
b) (5√6-√96):√3-√48×(√24+4√6)=
c) (3√14-√350):√7-)2√486-√294):√3=
d) √48×(2√75-√27+2√27)-√48×√12=
e) √243×√147-2√3×7√3+3√8(5√72+6√128)=
2) Transformati in fractii zecimale, impartind la numitorul comun :
13 supra 6 , 2 supra 5 , 7 supra 30, 101 supra 45
3) 6√3+√108-4√75+2√147 =
8√3+33√12-5√27=
URGENT, COROANA

Answer 1

a) (2√32-10√14) : (2√2) -(3√90-√3240):(3√5) =
=(8√2 - 10√7 ×√2) : (2√2) - (9√2×√5 - 18√2×√5) : (3√5)=
=4 - 5√7  - 3√2 + 6√2=
=4 - 5√7  + 3√2


b) (5√6-√96):√3-√48×(√24+4√6)=
=(5√6 - 4√6) : √3 - 4√3 * (2√6 + 4√6) =
=√6 : √3 - 4√3 * 6√6  =
=√2 - 24√18  =
=√2 - 72√2  =
=71√2

c) (3√14-√350):√7-)2√486-√294):√3=
=(3√14 - 5√14) : √7 - (18√6 - 7√6) :√3=
=(- 2√14) : √7 - (11√6) :√3=
=- 2√2  - 11√2=
=-13√2

d) √48×(2√75-√27+2√27)-√48×√12=
=4√3×(10√3-3√3+6√3)-4√3×2√3=
=4√3×13√3-8*3=
=52*3-24=132

e) √243×√147-2√3×7√3+3√8(5√72+6√128)=
=9√3×7√3-2√3×7√3+6√2(30√2+48√2)=
=63*3-14*3+6√2*78√2=
=189-42+936=1083

2)
13/6=2,1(6)
 2/5 =0,4
 7/30=0,2(3)
 101/45=2,2(4)
6=2*3
5=5
30=5*6
45=3²*5
cmmmc = 2*3²*5*6=540
13/6:540≈0,004
2/5:540≈0,0007
7/3:540≈0,004
101/45:540≈0.004

3) 6√3+√108-4√75+2√147 =
=6√3+6√3-20√3+14√3 =
=6√3
 
8√3+33√12-5√27=
=8√3+66√3-15√3=
=59√3