Question

Calculati va rog:

a) f(x)=(√3 ³ - 1)`

b) f(x)=(2sin2x)`

Answer 1

a) $f'(x)=(\sqrt{x^3}-1)'=(x^{\frac32}-1)'=(x^\frac32)'=\frac32x^{\frac32-1}=\frac32x^{\frac12}=\frac3{2\sqrt x}$

b) $f'(x)=(2\sin{2x})'=2(\sin{2x})'=2\cdot(2x)'\cos{2x}=4\cos{2x}$