Question

Calculați vă rog acest exercițiu!​

Answer 1

$= \dfrac{3}{\sqrt{7} - 3} + \dfrac{\sqrt{7} + 4 }{1} = \dfrac{3(\sqrt{7} + 3)}{(\sqrt{7} - 3)(\sqrt{7} + 3)} + \sqrt{7} + 4$

$= \dfrac{3\sqrt{7} + 9}{(\sqrt{7})^{2} - 3^{2} } + \sqrt{7} + 4 = \dfrac{3\sqrt{7} + 9}{7 - 9} + \sqrt{7} + 4$

$= - \dfrac{3\sqrt{7} + 9}{2} + \sqrt{7} + 4 = - \dfrac{3\sqrt{7} + 9}{2} + \dfrac{2(\sqrt{7} + 4)}{2}$

$= \dfrac{ - 3\sqrt{7} - 9 + 2\sqrt{7} + 8}{2} = \dfrac{ - \sqrt{7} - 1}{2} = \bf- \dfrac{\sqrt{7} + 1}{2}$