Question

Calculati.
Va rog,repede,ajutati-ma
Dau coroana

Answer 1

$c)3 \sqrt{2} \cdot(3 \sqrt{2}+ \sqrt{3} - \sqrt{2}(3 \sqrt{2}+ \sqrt{3})$
$9\cdot2+3 \sqrt{6}-3 \sqrt{6}-3=18-3=15$

$e)3 \sqrt{3} \cdot(3 \sqrt{3}+ \sqrt{5} - \sqrt{5}(3 \sqrt{3}+ \sqrt{5})=3^{3}+3 \sqrt{15} -3 \sqrt{15} -5= \\ \\ 27-5=22$

$g)6 \sqrt{2} \cdot(6 \sqrt{2}-5 \sqrt{3} )+5 \sqrt{3}(6 \sqrt{2}+5 \sqrt{3})= \\ \\ 36\cdot2-30 \sqrt{6} +30 \sqrt{6}-25\cdot3=72-75=-3$

Answer 2

Mult succes în continuare!