Question

Calculati valoarea expresiei algebrice 4ab-b²+a pentru a=3 supra lui 4, b=4 supra lui 3

Answer 1

4ab-b²+a=4* $\frac{3}{4} * \frac{4}{3} - \frac{4}{3} ^{2} + \frac{3}{4}$=4-$\frac{16}{9} + \frac{3}{4}$=$\frac{144-64+27}{36} = \frac{107}{36}$