Question

Calculati volumul de CO2 si masa apei necesare pentru formarea prin fotosinteza a glucozei cu masa de :a)15g b)1 tona.Ce volum de oxigen se elimina in atmosfera.

Answer 1

Prima data scriem reactia

6CO2 + 6H2O = C6H12O6 + 6O2


a) 15g glucoza
M C6H12O6 = 180g/mol
M CO2 = 44g/mol
M H2O = 18g/mol
M O2= 32g/mol

180g glucoza ..... 6×22.4 l CO2......6×18g H2O........6×22.4l O2
15g.......................x...............................y ........................z

x=15×6×22.4/180 = 11.2 l CO2
y= 15×6×18/180= 9g H2O
z= 15×6×22.4/180=11.2 l

b) 1000 kg glucoza

180kg glucoza......6×22.4 m^3 CO2.....6×18 kg H2O.....6×22.4 m^3 O2
1000.............................x....................................y............................z

x=1000×6×22.4/180=746.66m^3 CO2
y=1000×6×18/180=600 Kg H2O
z=1000×6×22.4/180=746.66 m^3 O2