Question

calculati volumul in conditii normale si numarul de molecule din 50 g Cl2.

Answer 1

p₀=10⁵ Pa

m=50 g=0,05 kg

T₀=273 K

μ=71 g/mol=0,071 kg/mol

υ=m/μ=0,05/0,071 =0,7 moli

p₀V=υRT₀=>V=υRT₀/p₀=8,314*0,7*273/10⁵=1,6*10⁻² l

υ=N/NA=>N=υ*NA=0,7*6,023*10²³=4,21*10²³ molecule