Question

Calculati volumul solutiei de 5 M de NaOH care neutralizeaza 664 g acid ftalic .

Answer 1

C6H4(COOH)2 + 2NaOH = Na2C6H4(COO)2 + 2H2O

M C6H4(COOH)2 =166g/mol
Nr moli C6H4(COOH)2 =664/166=4moli

1mol C6H4(COOH)2 ....2 moli NaOH
4moli C6H4(COOH)2 ....x=8 moli NaOH

1L sol NaOH...5moli NaOH
y L sol NaOH....8moli NaOH

y=8/5=1,6L