Question

calculati : x(1-√2)>4-2√8

Answer 1

$x(1-\sqrt{2})\ \textgreater \ 4-2\sqrt{8} =\ \textgreater \ x(1-\sqrt{2})\ \textgreater \ 4-2*2\sqrt{2} =\ \textgreater \ \\ =\ \textgreater \ x(1-\sqrt{2})\ \textgreater \ 4-4\sqrt{2} =\ \textgreater \ x(1-\sqrt{2})\ \textgreater \ 4(1-\sqrt{2})|:1-\sqrt{2} =\ \textgreater \ \\ =\ \textgreater \ x\ \textless \ 4 =\ \textgreater \ x \in (-\infty,4)$
Atentie! $1-\sqrt{2}\ \textless \ 0$