Question

calculati (x^2 +x supra 3)-(x^2 supra 3+2x)+(5x^2 supra 6-x supra 4)

Answer 1

a)(x+96)*3+236=1988=1988-236=1752
x+96=1752:3=584⇒x=584-96=488;x=488
b)4x-23=46-42+3x⇒x=23+4=27
c)5*[2*(3x+2)-11]=31-6=25
2*(3x+2)-11=25:5=5
(3x+2)=5+11=16
3x+2=16:2=8
3x+28⇒3x=6⇒x=6:3=2
d)x-10*[362+10*(24+6)]=100:10=10
x-10*(362+10*30)=10
x=10+6620
x=6630
e){2*[20-(5+x):6]-5}:9=20-17=3
2*[20-(5+x):6]-5=3*9=27
2*[20-(5+x):6=27+5=32
20-(5+x):6=32:2=16
(5+x):6=20-16=4
5+x=6*4=24
x=24-5
x=19
2)a)

b)

c)
d)enuntul este gresit!



e)