Question

calculati:
(x-3)2 (totul la a 2 a)
(4x+1)2
(3x-4) (3x+4)

Answer 1

sper că te-am ajutat

Answer 2

$\star) {(x - 3)}^{2} = {x}^{2} - 2 \times x \times 3 + {3}^{2}$

$= {x}^{2} - 6x + 9$

$={x}^{2}-3(2x-3)$

$\star) {(4x + 1)}^{2} = {(4x)}^{2} + 2 \times 4x \times 1 + {1}^{2}$

$= 16 {x}^{2} + 8x + 1$

$= 8(2 {x}^{2} + x) + 1$

$\star)(3x - 4)(3x + 4) = {(3x)}^{2} - {4}^{2}$

$= 9 {x}^{2} - 16$

Formule :

${(a \pm b)}^{2} = {a}^{2} \pm2ab + {b}^{2}$

$(a - b)(a + b) = {a}^{2} - {b}^{2}$