Question

Calculati:
(x+3) la puterea a 2-a
(2x+3) la puterea a 2-a
(2x+3y) la puterea a 2-a
(2x-3y) la puterea a 2-a
(B+5) la puterea a 2-a
(4a-2b)•(4a+26)
(5x-3)•(5x+3)
(3x+4y)•(3x-4y)
(6a-3b)•(6a+3b)
Dau coroana

Answer 1

$(x + 3) {}^{2} = x { }^{2} + 2 \times x \times 3 + 3 {}^{2}$
$(x - 3) {}^{2} = x + 2 \times x \times 3 - 3 {}^{2}$
acestea sunt formulele pentru toate exercitiile la puterea a 2 a *cu primul exercitiu ca exemplu*

Answer 2

(x+3)^2=(x+3)(x+3)=x(x+3)+3(x+3)=x^2+3x+3x+9=x^2+6x+9
(2x+3)^2=(2x+3)(2x+3)=2x(2x+3)+3(2x+3)=4x^2+6x+6x+9=4x^2+12x+9
(2x+3y)^2=(2x+3y(2x+3y)=2x(2x+3y)+3y(2x+3y)=4x^2+6xy+6xy+9y^2=4x^2+12xy+9y^2
(2x-3y)^2=(2x-3y(2x-3y)=2x(2x-3y)-3y(2x-3y)=4x^2-6xy-6xy+9y^2=4x^2-12xy+9y^2
(B+5)^2=(B+5)(B+5)=B(B+5)+3(B+5)=B^2+5B+5B+15=B^2+10B+15
(4a-2b)(4a+2b)=4a(4a+2b)-2b(4a+2b)=16a^2+8ab-8ab-4b^2=16a^2-4b^2
(5x-3)(5x+3)=5x(5x+3)-3(5x+3)=25x^2+15x-15x-9=25x^2-9
(3x+4y)(3x-4y)=3x(3x-4y)+4y(3x-4y)=9x^2-12xy+12xy-16y^2=9x^2-16y^2
(6a-3b)(6a+3b)=3(2a-b)3(2a+b)=9(2a-b)(2a+b)=9(2a(2a+b)-b(2a+b))=9(4a^2+2ab-2ab-b^2)=9(4a^2-b^2)