Question

calculati x din proportiile
a) $\frac{x-1}{1+ \frac{1}{2} } = \frac{ \frac{7}{3}-1 }{3- \frac{3}{2} } , x$∈Q
b) $\frac{2x+1}{4x+3} = \frac{1}{3}$ , x apartine Q \{${- \frac{3}{4} }$}

Answer 1

7/3-1=(7-3)/3=4/3
1+1/2=3/2
3-3/2=6-3/2=3/2
(x-1)/(3/2)=(4/3)/(3/2)
x-1=4/3
x=4/3+1
x=7/3

(2x+1)/(4x+3)=1/3
6x+3=4x+3
6x=4x
x=0