Question

Calculaţi x + y şi x - y dacă
E URGENT ​

Answer 1

Răspuns:

a)

x+y = -16√2

x-y = 12√2

b)

x+y = -√3

x-y = 3√3

c)

x+y = 3√5

x-y = -21√5

d)

x+y = -2√6

x-y = 6√6

Explicație pas cu pas:

a)

$x = 5\sqrt{2} - 7\sqrt{2} = -2\sqrt{2}$

$y = -\sqrt{2} -13\sqrt{2} = -14\sqrt{2}$

$x+y = -2\sqrt{2} - 14\sqrt{2} = -16\sqrt{2}$

$x-y = -2\sqrt{2} + 14\sqrt{2} = 12\sqrt{2}$

b)

$x = 4\sqrt{3} - 3\sqrt{3} = \sqrt{3}$

$y = -6\sqrt{3} +4\sqrt{3} = -2\sqrt{3}$

$x+y = \sqrt{3} - 2\sqrt{3} = -\sqrt{3}$

$x-y = \sqrt{3} +2\sqrt{3} = 3\sqrt{3}$

c)

$x = -2\sqrt{5} -7\sqrt{5} = -9\sqrt{5}$

$y = 13\sqrt{5} - \sqrt{5} = 12\sqrt{5}$

$x+y = -9\sqrt{5} + 12\sqrt{5} = 3\sqrt{5}$

$x - y = -9\sqrt{5} - 12\sqrt{5} = -21\sqrt{5}$

d)

$x = -7\sqrt{6} +9\sqrt{6} = 2\sqrt{6}$

$y = 4\sqrt{6} - 8\sqrt{6} = -4\sqrt{6}$

$x+y = 2\sqrt{6} - 4\sqrt{6} = -2\sqrt{6}$

$x-y = 2\sqrt{6} +4\sqrt{6} = 6\sqrt{6}$

Answer 2

Explicație pas cu pas:

a)

$x = 5 \sqrt{2} - 7 \sqrt{2} = - 2 \sqrt{2}$

$y = - \sqrt{2} - 13 \sqrt{2} = - 14 \sqrt{2}$

$x + y = - 2 \sqrt{2} + ( - 14\sqrt{2}) = - 2 \sqrt{2} - 14 \sqrt{2} = - 16 \sqrt{2}$

$x - y = - 2 \sqrt{2} - ( - 14 \sqrt{2}) = - 2 \sqrt{2} + 14\sqrt{2} = 12 \sqrt{2}$

b)

$x = 4 \sqrt{3} - 3 \sqrt{3} = \sqrt{3}$

$y = - 6 \sqrt{3} + 4 \sqrt{3} = - 2 \sqrt{3}$

$x + y = \sqrt{3} + ( - 2 \sqrt{3}) = \sqrt{3} - 2 \sqrt{3} = - \sqrt{3}$

$x - y = \sqrt{3} - ( - 2 \sqrt{3}) = \sqrt{3} + 2 \sqrt{3} = 3\sqrt{3}$

c)

$x = - 2 \sqrt{5} - 7 \sqrt{5} = - 9 \sqrt{5}$

$y = 13 \sqrt{5} - \sqrt{5} = 12 \sqrt{5}$

$x + y = - 9 \sqrt{5} + 12 \sqrt{5} = 3 \sqrt{5}$

$x - y = - 9 \sqrt{5} - 12 \sqrt{5} = - 21 \sqrt{5}$

d)

$x = - 7 \sqrt{6} + 9 \sqrt{6} = 2 \sqrt{6}$

$y = 4 \sqrt{6} - 8 \sqrt{6} = - 4 \sqrt{6}$

$x + y = 2 \sqrt{6} + ( - 4 \sqrt{6}) = 2 \sqrt{6} - 4 \sqrt{6} = - 2 \sqrt{6}$

$x - y = 2 \sqrt{6} - ( - 4 \sqrt{6}) = 2 \sqrt{6} + 4 \sqrt{6} = 6 \sqrt{6}$