Question

Calculaţi x'y+y'x pentru:
x=8³³:[4³²×2³⁴+(2⁵×2²⁰)⁵÷(16×2²³)+(7⁵:7⁵-1)³²×4].
y=[(11-0¹¹)×(3³-3²)+1²⁰²⁰]×(3²-2³)-3²×2.

VA ROG URGENTT!!!
DAU COROANA!!!!!!​

Answer 1

Răspuns:

x=8³³:[4³²•2³⁴+(2⁵•2²⁰)⁵:(16•2²³)+(7⁵:7⁵-1)³²•4]

x=8³³:[(2²)³²•2³⁴+(2²⁵)⁵:(2⁴•2²³)+(7⁰-1)³²•4

x=8³³:[2⁶⁴•2³⁴+2¹²⁵:2²⁷+(1-1)³²•4]

x=8³³:(2⁹⁸+2⁹⁸+0³²•4)

x=(2³)³³:[(2⁹⁸+2⁹⁸+0•4)

x=2⁹⁹: (2⁹⁸+2⁹⁸+0)

x=2⁹⁹: 2⁹⁸•(1+1+0)

x=2⁹⁹:2⁹⁸•2

x=2⁹⁹: 2⁹⁹

x=1

La y numai scriu exercițiu încep direct cu rezolvarea

y=[(11-0¹¹)•(3³-3²)+1²⁰²⁰]•(3²-2³)-3²•2

y=[(11-0)•(27-9)+1]•(9-8)-3²•2

y=(11•18+1)•1-3²•2

y=(198+1)•1-9•2

y=(198+1)•1-18

y=199•1-18

y=199-18

y=181